InterviewSolution
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InterviewSolution
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The molecules of a given mass of gas have a rms velocity of `200 m//sec at 127^(@)C and 1.0 xx 10^(5) N//m^(2)` pressure. When the temperature is `127^(@)C` and pressure is `0.5 xx 10^(5) N//m^(2)` the rms velocity in `m//sec` will beA. `100(sqrt(2))/3`B. `100(sqrt(2))`C. `400/(sqrt(3))`D. None of these |
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Answer» Correct Answer - C Change in pressure will not affect the rms velocity of molecules. So we will calculate only the effect of temperature. As, `v_(rms) prop sqrt(T)` `:. (v_(300^@))/(v_(400^@)) = sqrt((300)/(400)) = sqrt((3)/(4)) implies (200)/(v_(400)) = sqrt(3/4)` `implies v_(400) = (200xx2)/(sqrt(3)) = (400)/(sqrt(3)) m//s`. |
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