The moment of inertia of a body about a given axis is 1.2 kg m^2. Initially, the body is at rest. In order to produce a rotational kinetic energy of 6000 joule, an angular acceleration of 25 rad/s^2 must be applied about that axis for a duration of

The moment of inertia of a body about a given axis is 1.2 kg m^2. Init

1.	The moment of inertia of a body about a given axis is 1.2 kg m^2. Initially, the body is at rest. In order to produce a rotational kinetic energy of 6000 joule, an angular acceleration of 25 rad/s^2 must be applied about that axis for a duration of
Answer» 4 s 2 s 8 s 10 s SOLUTION :Rotational KINETIC energy , `K_(R) = (1)/(2) I omega^(2) = (1)/(2) I alpha^(2) t^(2)` Substituting the given values , we get `6000 = (1)/(2) xx 1.2 xx (25)^(2) xx t^(2)` or `t^(2) = 16` or t = 4s