The moment of inertia of a body about a given axis is `1.2 kg m^(2)`. Initially, the body is at rest. In order to produce a rotational `KE` of `1500 J`, for how much duration, an acceleration of `25 rad s^(-2)` must be applied about that axis ?A. ` 4 s`B. ` 2 s`C. ` 8 s`D. ` 10 s`

The moment of inertia of a body about a given axis is `1.2 kg m^(2)`.

1.	The moment of inertia of a body about a given axis is `1.2 kg m^(2)`. Initially, the body is at rest. In order to produce a rotational `KE` of `1500 J`, for how much duration, an acceleration of `25 rad s^(-2)` must be applied about that axis ?A. ` 4 s`B. ` 2 s`C. ` 8 s`D. ` 10 s`
Answer» `K=(1)/(2)I omega^(2)implies 1500=(1)/(2)xx1.2xxomega^(2)` `omega=50 rad//s=omega_(0)+alpha timplies 50=25timplies t=2 s`

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The moment of inertia of a body about a given axis is `1.2 kg m^(2)`. Initially, the body is at rest. In order to produce a rotational `KE` of `1500 J`, for how much duration, an acceleration of `25 rad s^(-2)` must be applied about that axis ?A. ` 4 s`B. ` 2 s`C. ` 8 s`D. ` 10 s`

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