The moment of inertia of a circular ring about one of its diameters is I . What will be its moment of inertia about a tangent parallel to the diameter?

The moment of inertia of a circular ring about one of its diameters is

1.	The moment of inertia of a circular ring about one of its diameters is I . What will be its moment of inertia about a tangent parallel to the diameter?
Answer» 4 I 2 I `(3)/(2) I` `3 I` SOLUTION :`I = (1)/(2) MR^(2) ""… (i)` ACCORDING to theorem of parallel axes , the moment of inertia about the given axis is `I. = (1)/(2) MR^(2) + MR^(2) = (3)/(2) MR^(2) = 3I ""` (Using (i))