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The moment of inertia of a fly wheel making 300 revolutions per minute is 0.3 kgm^(2) . Find torque required to bring it to rest in 20 s. |
Answer» <html><body><p></p>Solution :`n_(1)`=300 <a href="https://interviewquestions.tuteehub.com/tag/rpm-615000" style="font-weight:bold;" target="_blank" title="Click to know more about RPM">RPM</a>=`(300)/(60)=5rps,1=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>.3 kgm^(2)` <br/>`omega_(1)=2pin_(1)=2pixx5=10pi,omega_(2)=2pin_(2)=0` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> tau=(0.3xx(0-10pi))/(<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)=(-0.3xx10pi)/(20)=-0.15 pi=-0.471 <a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>`</body></html> | |