The moment of inertia of a fly wheel making 300 revolutions per minute is 0.3 kgm^(2) . Find torque required to bring it to rest in 20 s.

The moment of inertia of a fly wheel making 300 revolutions per minute

1.	The moment of inertia of a fly wheel making 300 revolutions per minute is 0.3 kgm^(2) . Find torque required to bring it to rest in 20 s.
Answer» Solution :`n_(1)`=300 RPM=`(300)/(60)=5rps,1=0.3 kgm^(2)` `omega_(1)=2pin_(1)=2pixx5=10pi,omega_(2)=2pin_(2)=0` `THEREFORE tau=(0.3xx(0-10pi))/(20)=(-0.3xx10pi)/(20)=-0.15 pi=-0.471 NM`