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The moment of inertia of a fly wheel making 300 revolutions per minute is 0.3kgm^(3), find torque required to bring it to rest in 20 s. |
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Answer» Solution :TORQUE `TAU=Ialpha=I((omega_(2)-omega_(1)))/(t)` `:.tau=(0.3xx(0-10pi))/(20)` `=-0.15pi=-0.471Nm` |
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