The moment of inertia of a flywheel having kinetic energy 360 J and angular speed of 20 rad/s is

The moment of inertia of a flywheel having kinetic energy 360 J and an

1.	The moment of inertia of a flywheel having kinetic energy 360 J and angular speed of 20 rad/s is
Answer» 18 KG `m^(2)` 1.8 kg `m^2` 2.5 kg `m^2` 9 kg `m^2` Solution :Given kinetic ENERGY , K = 360 J Angular speed , `omega = 20` rad/s . As `K = (1)/(2) I omega^(2)` (where I = moment of inertia) `therefore I = (2K)/(omega^2) = (2 xx 360)/(20 xx 20) = 1.8 kg m^2`