The moment of inertia of a flywheel making 300 revolutions per minute is 0.3 kgm^2 . Find the torque required to bring it to rest in 20s.

The moment of inertia of a flywheel making 300 revolutions per minute

1.	The moment of inertia of a flywheel making 300 revolutions per minute is 0.3 kgm^2 . Find the torque required to bring it to rest in 20s.
Answer» SOLUTION :Torque `TAU = I alpha = I((omega_(2)-omega_(1)))/(t)` `therefore tau = (0.3xx(0-10pi))/(20) = -0.15 pi = -0.471 Nm`.