The moment of inertia of a rod about an axis through its centre and perpendicular to it is (1)/(12)ML^(2) (where M is the mass and L, the length of the rod). The rod is bent in the middle so that the two halves make an angle 60^(@). The moment of inertia of the bent rod about the same axis would be..........

The moment of inertia of a rod about an axis through its centre and pe

1.	The moment of inertia of a rod about an axis through its centre and perpendicular to it is (1)/(12)ML^(2) (where M is the mass and L, the length of the rod). The rod is bent in the middle so that the two halves make an angle 60^(@). The moment of inertia of the bent rod about the same axis would be..........
Answer» `(1)/(48)ML^(2)` `(1)/(12)ML^(2)` `(1)/(24)ML^(2)` `(ML^(2))/(8sqrt(3))` SOLUTION : Moment of inertia of UNIFORM rod about ONE end = `(ML^(2))/(3)` Moment of inertia of a rod about an AXIS passing through O and perpendicular to the plane of the rod will be `I.=2((M)/(2))(((L)/(3))^(2))/(3)` `=(ML^(2))/(4xx3)` `therefore I.=(ML^(2))/(12)`