1.

The moment of inertia of a seme circular ring of mass M and radius R about an axis lying in the plane which is passing through its centre and at an angle theta with the line joining its ends (as shown) is :

Answer»

`("MR"^(2))/(4)" at "theta=0^(@)`
`("MR"^(2))/(2)" if "theta=0^(@)`
`("MR"^(2))/(2)" if "theta=45^(@)`
`("MR"^(2))/(2)" if "theta=90^(@)`

ANSWER :B::C::D


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