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The moment of inertia of a solid flywheel about its axis is `0.1 kg-m^(2)`.A tangential force of 2 kg-wt. is applied round the circumference of the flywheel with the help of a string and mass arrangement as shown in the figure. If the radius of the wheel is 0.1 m, find the acceleration `("in rad/sec"^(2))` of the mass : A. 163.3B. 16.3C. 81.66D. 8.16 |
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Answer» Correct Answer - B `a=(m"g")/(m+I//r^(2))=(19.6)/12` `alpha=a/R="16.33 "rad//s^(2)` |
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