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The moment of inertia of a thin uniform rod of mass M and length l about an axis perpendicular to the rod through its centre is I. The moment of inertia of the rod through its end point is |
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Answer» `(I)/(4)` `l = (Ml^(2))/(12) "" … (i)` The moment of inertia of the rod through its end POINT is `I. = (Ml^2)/(3) = 4 ((Ml^2)/(12)) = 4L ""` (Using (i)) |
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