The moment of inertia of the body about an axis is 1.2 kg `m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angualr acceleration of 25 `rad/s^(2)` must be applied about the axis for the duration ofA. 2sB. 4sC. 8sD. 10 s

The moment of inertia of the body about an axis is 1.2 kg `m^(2)`. Ini

1.	The moment of inertia of the body about an axis is 1.2 kg `m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angualr acceleration of 25 `rad/s^(2)` must be applied about the axis for the duration ofA. 2sB. 4sC. 8sD. 10 s
Answer» a) Rotational kinetic energy, `1/2 Iomega^(2)` According to question, `1/2Iomega^(2)`=1500 `1/2l(alphat)^(2) = 1500 ` `(1.2) xx (25)^(2) xx t^(2) = 3000` `1.2 xx 625 xx t^(2) = 3000` `t^(2) = (3000/(1.2 xx 625)` = 4 `t=2s`

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The moment of inertia of the body about an axis is 1.2 kg `m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angualr acceleration of 25 `rad/s^(2)` must be applied about the axis for the duration ofA. 2sB. 4sC. 8sD. 10 s

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