The moment of the force vecF= 4 hati + 5hatj - 6hatk at (2 , 0 , -3) , about the point (2 , -2 ,-2) , is given by

The moment of the force vecF= 4 hati + 5hatj - 6hatk at (2 , 0 , -3) ,

1.	The moment of the force vecF= 4 hati + 5hatj - 6hatk at (2 , 0 , -3) , about the point (2 , -2 ,-2) , is given by
Answer» `- 8 HATI - 4hatj - 7hatk` `-4hati - hatj- 8hatk` `-7hati - 8 hatj - 4hatk` `-7hati - 4hatj - 8hatk` Solution : Moment of the force is , `vectau = (vecr - vecr_(0)) xx vecF` Here , `vecr_(0) = 2 hati - 2hatj - 2hatk` and `vecr = 2 hati + 0 hatj - 3hatk` `therefore vecr - vecr_(0) = (2 hati +0 hatj - 3hatk) - (2hati - 2hatj - 2hatk) = 0 hati + 2hatj - hatk` `therefore tau = \|{:(hati , hatj , hatk) , (0, 2 , -1) , (4 , 5 , -6):}\| = -7hati - 4hatj - 8hatk`