The momenta of a body in two perpendicular directions at any time 't' are given by P_(X)=2t^(2)+6 and P_(Y)=(3t^(2))/(2)+3. The force acting on the body at t=2 sec is

The momenta of a body in two perpendicular directions at any time 't'

1.	The momenta of a body in two perpendicular directions at any time 't' are given by P_(X)=2t^(2)+6 and P_(Y)=(3t^(2))/(2)+3. The force acting on the body at t=2 sec is
Answer» 5 UNITS 2 units 10 units 15 units Solution :`F_(X)=(dP_(x))/(dt), F_(y)=(dP_(y))/(dt), F=sqrt(F_(x)^(2)+F_(y)^(2))`