1.

The momentf inertiaof a solidcylinder about an axis parallelto itslengthand passingthroughits centreis equalto itsmoment ofinertiaabout an axisperpendicular to thelength of cylinder and passingthroughitscentre .The ratio of radius of cylinderand itslength is

Answer»

`1:sqrt(2)`
`1:2`
`1:sqrt(3)`
`1,3`

SOLUTION :`(MR^(2))/(2) = (ML^(2))/(12) + (MR^(2))/4 `


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