The moments of inertia of two rotating bodies A and B are I_(A) and I_(B)(I_(A) gtI_(B)). If their angular momenta are equal, then

The moments of inertia of two rotating bodies A and B are I_(A) and I_

1.	The moments of inertia of two rotating bodies A and B are I_(A) and I_(B)(I_(A) gtI_(B)). If their angular momenta are equal, then
Answer» Kinetic energy of A = Kinetic energy of B Kinetic energy of A `gt` Kinetic energy of B Kinetic energy of A `lt` Kinetic energy of B Kinetic energy of the TWO BODIES cannot be compared with the GIVEN data. Solution :`I_(A) omega_(A) = I_(B) omega_(B), therefore (omega_(A))/(omega_(B)) = (I_(B))/(I_(A)) "" … (i)` Kinetic energy = `(1)/(2) I omega^(2)` `therefore ((KE)_(A))/((KE)_(B)) = ((1)/(2) I_(A) omega_(A)^(2))/((1)/(2) I_(B) omega_(B)^(2)) = (I_(A))/(I_(B)) XX ((I_(B))/(I_(A)))^(2)= (I_(B))/(I_(A)) ""` (USING (i)) As `I_(A) gt I_(B)` (Given) , `therefore (KE)_(A) lt (KE)_(B)`