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The moments of inertia of two rotating bodies `A` and are `I_A` and `I_B(I_A gt I_B)`. If their angular momenta are equal then.A. Kinetic energy of `A` = Kinetic energy of `B`B. Kinetic energy of `A` gt Kinetic energy of `B`C. Kinetic energy of `A` lt Kinetic energy of `B`D. Kinetic energy of the two bodies cannot be compared with given data. |
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Answer» Correct Answer - C ( c) `I_A omega_A = I_B omega_B` (Given) :. `(omega_A)/(omega_A) = (I_B)/(I_A)` …(i) Kinetic energy `= (1)/(2) I omega^2` :. `((K.E.)_A)/((K.E.)_B) = ((1)/(2) I_A omega_A^2)/((1)/(2) I_B omega_B^2)` =`(I_A)/(I_B)xx ((I_B)/(I_A))^2` (Given (i)) =`(I_B)/(I_A)` As `I_A gt I_B` (Given) :. `(K.E.)_A lt (K.E.)_B`. |
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