

InterviewSolution
Saved Bookmarks
1. |
The momentum of a body is doubled. By what percentage does its kinetic energy increase ? |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>=(p^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>)rArr (K_(1))/(K_(2))=(p_(1)^(2))/(p_(2)^(2))`<br/>Let `K_(1)=K, p_(1)=p` then `p_(2)=2p, K_(2)=?`<br/>`(K)/(K_(2))=(p^(2))/((2p)^(2)), K_(2)=4K`.<br/>% increase in kinetic energy = `("Increase in kinetic energy")/("Initial kinetic energy")<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a>`<br/>`(K_(2)-K_(1))/(K_(1))xx100=(4K-K)/(K)xx100=300%`</body></html> | |