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The momentum of a particle is given by `vecP= (2 sin t hati- 2cos t hatj)kgm//s`. Select the correct option:A. Momentum `vecp` of the particle is always perpendicular to `vecF`B. Momentum `vecp` of the particle is always parallel t `vecF`C. Magnitude of momentum remains constantD. None of the above |
Answer» Correct Answer - A::C `vecp =2 sin t hati - 2 cos t hatj` `vecF = (d vecp)/(dt)= 2 cos t hati + 2 sin that j` `therefore" "vecF. vecp = 0 rArr vecF botvecp` Also, `|vecp|= sqrt((2sin t)^(2)+ (2 cos t)^(2) )= 2=` constant. |
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