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The momentum of inertia of a body rotating about a given axis is `12.0 kg m^(2)` in the SI system . What is the value of the moment of inertia in a system of units in which the unit of lengths is `5 cm` and the unit of mass is `10 g`?A. ` 2.4 xx 10^(3)`B. `6.0 xx 10^(3)`C. `5.4 xx 10^(5)`D. `4.8 xx 10^(5)` |
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Answer» Correct Answer - D ` n_(2) = n_(1) ((M_(1))/(M_(2)))^(a) ((L_(1))/(L_(2)))^(b) ((T_(1))/(T_(2)))^( c )` Dimensional formula of moment of interia ` = [ML^(2) T^(0)]` :. ` a = 1, b= 2 , c = 0 ` `n_(1) = 12.0 , M_(1) = 1 kg , M_(2) = 10 g ` `L_(1) = 1 m , L_(2) = 5 cm , T_(1) = 1 s, T_(2) = 1 s` `n_(2) = 12.0 ((1 kg)/( 10 g)) ^(1) ((1 m)/( 5 cm))^(2) ((1 s)/( 1s))^(0)` ` = 12 xx ((1000 g )/( 10 g)) ^(1) (( 100 cm) /(5 cm))^(2) xx 1` ` = 12 xx 100 xx 400 = 4.8 xx 10^(5)` |
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