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The momentum p of a particle changes with the t according to the relation `dp/dt=(10N)+(2N/s)t`. If the momentum is zero at t=0, what will the momentum be at t=10?. |
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Answer» Correct Answer - B `(dp)/(dt)=(10B)+(2N/S)t` Momentum is zero t t=0 Momentum at t=10 sec will be `dp= [(10N)+2N^(-1)t)]dt` Integrating `int^10_0 dp=int^10_0 10 dt+ int ^10_0(2tdt) =[10t+2t^2/2]^10_0 =10xx10-0+100 =100+100=200 kg. m/s` |
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