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The momentumof a body increased doubled .What is the percentage of increment in its kinetic energy ? |
Answer» <html><body><p></p>Solution :`K = 1/mv^(2) = (p^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>) "" …(1)`<br/> `K = (p^(2))/(2m) ""….(2)`<br/> `p. =2p ` <br/> ` :. K = (4p^(2))/(2m)`<br/> ` :. K . = <a href="https://interviewquestions.tuteehub.com/tag/4k-318773" style="font-weight:bold;" target="_blank" title="Click to know more about 4K">4K</a> `<br/> Increase in <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy= `(DeltaK)/K xx100` <br/> `= (3K)/K <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 100` <br/> = <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> %</body></html> | |