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The Moon Io orbits jupiter once in 1.769 days. The orbital radius of the Moon Io is 421700 Km. Caculate the mass of jupiter? |
Answer» <html><body><p></p>Solution :Kepler.s <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> law is <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> to find the mass of the planet<br/> `T^(2) = (4pi^(2))/(GM) (R+h)^(2)`<br/> ` M = (4pi^(2))/(GT^(2)) (R+h)^(2)(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>(3.14)^(2) xx (421700 xx10^(3))^(2))/(6.67 xx10^(11) xx (1.769xx86400)^(2))`<br/>` = (39.4384 xx 7.499128631xx10^(<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>))/(6.67xx10^(-11) xx 2.336055469 xx10^(10))`<br/> ` = (295.7536 xx10^(25))/(1.5581 ) = 189.8169 xx10^(25)`<br/> `M = 1.898 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>)` kg</body></html> | |