The Moon lo orbits Jupiter once in 1.769 days. The orbital radius of the Moon lo is 421700 km. Calculate the mass of Jupiter?

The Moon lo orbits Jupiter once in 1.769 days. The orbital radius of t

1.	The Moon lo orbits Jupiter once in 1.769 days. The orbital radius of the Moon lo is 421700 km. Calculate the mass of Jupiter?
Answer» Solution :`{:("TIME period of"),("the moon T"):}}=1.769"days"` `{:("Orbital radius"),("of the Moon"):}}=4217xx10^(2)km` Time period `T^(2)=(4pi^2)/(GM_J)(R_(M)+h)^(3)` `M_(J)` = Mass of Jupiter `GM_(J)=(4pi^(2)R_(M)^(3))/(T^2)[hltltR_(E)]` `{:("MEAN radius of"),("the moon" R_(M)):}}=1.737.1xx10^(3)m` `M_(J)=(4pi^(2)R_(M)^(3))/(GT^2)` Mass Jupiter `M_(J)=(4xx(3x14)^(2)xx(1737xx10^3)^(3))/(6.67xx10^(-11)xx(1.769)^(2))` `=(20668xx10^(27))/(20872xx10^(-11))` `=0.99022xx10^(27+11)` `=990226xx10^(38-5)` `=990226xx10^(33)` `=0.990226xx10^(27)` `~=1xx10^(27)kg`