1.

The most commonly used reducing agent is ……..

Answer»

`AlCl_3`
`PbCl_3`
`SnCl_4`
`SnCl_2`

SOLUTION :In `SnCl_2 , Sn^(2+)`can be EASILY oxidized to `Sn^(4+)` because +4 oxidation STATE of Sn is more stable than +2 oxidation state. Hence, `SnCl_2` ACTS as a reducing AGENT.
e.g., `SnCl_2 + 2FeCl_3 to SnCl_4 + 2FeCl_2`
`SnCl_2+ 2FeCl_3 to 2FeCl_2+ SnCl_4`
`SnCl_2 +2CuCl_2 to 2CuCl_2 + SnCl_4`


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