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The motion of a particle along a straight line is described by equation : `x = 8 + 12 t - t^3` where `x` is in metre and `t` in second. The retardation of the particle when its velocity becomes zero is.A. `24 ms^(-2)`B. zeroC. `6 ms^(-2)`D. `12 ms^(-2)` |
Answer» Correct Answer - D Given, `x=8+12t-t^(3)` We know, `upsilon=(dx)/(dt)` and `a=(d upsilon)/(dt)` So, `upsilon=12-3t^(2)` and `a=-6t` At `t = 2 s` `upsilon = 0` and `a = - 6t` `rArr a=-12 ms(-2)` So, ratardation of the particle `= 12 ms^(-2)`. |
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