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The motion of a particle along the x-axis is described by the following velocity function v(t)={:{((t^(3)+t^(2)+1),0 le t lt 3,"sec"),((2t+5),3 le t lt 5,"sec"),((t^(2)-6t),5 le t,"sec"):} where v is in m/sec and t is in second If initially, the particle was at x=0, then the position of particle at t=2 second will be |
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Answer» 10 m |
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