1.

The motion of a particle of mass m is given by x = 0 for t lt 0 s, x(t) = A sin 4pit for 0 lt t lt (1/4) s (A gt 0) andx =0 for t gt(1/4) s whichof the following statements is true ?

Answer»

The force at `t=(1/8)` on the particle is `-16 pi^(2)A-m`
The particle is acted UPON by on impulse of magnitude `4pi^(2)` A - m at t = 0 s and `t=(1/4)s`
The particle is not acted upon by any force
The particle is not acted upon by a constant force

Solution :(A,B,D )
x= 0for `tle0 ` sec
for0 `ltt lt (1)/(4)s`
`v= (dx )/(dt )= 4 piA cos ( 4pit ) `
Att = `(1)/( 8)` sec
`=-16 pi^(2)A SIN ((pi)/( 2))`
Nowforce F = ma (t )
`=m[-16 pi^(2) A]`
`=-16 pi^(2)Am`
Now impulseof force CHANGEIN mometum
`=(-16pi^(2) mA sin pi ) ^(1/4) = 0`
Theimpulsechangein linearmomentuma
`t=0` issameas at`t= (1)/(4) ` sec


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