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The `Mw` of a oxide of an element is 44. The `Ew` of the element is 14. The atomic weight of the element isA. (a)`14`B. (b)`28`C. (c )`42`D. (d)`56` |
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Answer» Correct Answer - A Let the formula of oxide `=M_(2)O_(x)=44` `2xxM+x xx 16 =44` `2(Exx x)+x xx16=44` `2(14xx x)+16 x=44` `:. X=1` atomic weight `=14xx1=14` |
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