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The negation of p ∧ (q → r) is(A) p v (~ q v r) (B) ~ p ∧ (q → r) (C) ~ p ∧ (~ q → ~ r) (D) ~ p v (q ∧ ~ r) |
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Answer» (D) ~ [p ∧ (q → r)] ≡ ~p v ~(q → r) ….(Negation of conjunction) ≡ ~p v (q ∧ ~r) .…(Negation of implication) |
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