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The neutron is a particle with zero charge still it has a non-zero magnetic moment with z-component `9.66 xx 10^(-27) A-m^(2)`. This can be explained by the internal structure of the neutron. The evidence indicates that a neutron is composed of three fundamental particles calleed quarks : an `"up"` (u) quark, of charge `+ (2e)/(3)`, and two `"down"` (d) quarks, each of change `- (e)/(3)`. The combinations of the three quarks prodcues a net charge of `(2e)/(3) - e/3 - e/3 = 0`. If the quarks are in motion they can produce a non-zero magnetic moment. As a very simple model, suppose the u quark moves in a counter clockwise circular path and the d quarks move in a clockwise circular path, all of the radius r and all with the same speed v see figure. Determine the magnitude of the magnetic moment due of the circular u quark :-A. `(evr)/(3pir)`B. `(2evr)/(3)`C. `(4evr)/(3)`D. `evr` |
Answer» Correct Answer - A `M_(u)=(evr)/3` |
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