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The nitrogen containing compound produced in the reaction of HNO_(3) with P_(4)O_(10) |
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Answer» can be prepared by reaction of `P_(4)andHNO_(3)` `N_(2)O_(5)` cannot be prepared by action of `HNO_(3)` on `P_(4)` but gives `H_(3)PO_(4)` `P_(4)+10HNO_(3)to4H_(3)PO_(4)+20NO_(2)+4H_(2)O` `N_(2)O_(5)` has 54 electrons `(2xx7+5xx8)` and hence is diamagnetic `N_(2)O_(5)` does not CONTAIN N-N bond. REFER to structure is Table 11.14, page 11//120. `N_(2)O_(5)` reacts with Na producing `NO_(2)` `Na+N_(2)O_(5)toNaNO_(3)+NO_(2)` (brown gas) Thus, option (b) and (d) are correct. |
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