1.

The nitrogen containing compound produced in the reaction of HNO_(3) with P_(4)O_(10)

Answer»

can be prepared by reaction of `P_(4)andHNO_(3)`
is diamaganetic
contains N-N BOND
reacts with Na-metal producing brown gas

Solution :`4HNO_(3)+P_(4)O_(10)to4HPO_(3)+2N_(2)O_(5)`
`N_(2)O_(5)` cannot be prepared by action of `HNO_(3)` on `P_(4)` but gives `H_(3)PO_(4)`
`P_(4)+10HNO_(3)to4H_(3)PO_(4)+20NO_(2)+4H_(2)O`
`N_(2)O_(5)` has 54 electrons `(2xx7+5xx8)` and hence is diamagnetic `N_(2)O_(5)` does not CONTAIN N-N bond. REFER to structure is Table 11.14, page 11//120.
`N_(2)O_(5)` reacts with Na producing `NO_(2)`
`Na+N_(2)O_(5)toNaNO_(3)+NO_(2)` (brown gas)
Thus, option (b) and (d) are correct.


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