The no. Of atoms of Cr and o are 4.8*10power10 and 9.6 *10 power 10 it

1.	The no. Of atoms of Cr and o are 4.810power10 and 9.6 10 power 10 it's empirical formula is
Answer» Explanation: We know that the valency of Oxygen is 2 so the oxidation state is -2 Hence let's take the oxidation state of CHROMIUM to be x so $x(4.8 \times {10}^{10}) - 2(9.6 \times {10}^{10}) = 0 = >$ $4.8 \times {10}^{10}(x - 4) = 0 = > x = 4$ Hence the oxidation state is 4 so one atom of Chromium is oxidised by two atoms of Oxygen so Empirical formula is CrO2. HOPE it HELPS you.

The no. Of atoms of Cr and o are 4.810power10 and 9.6 10 power 10 it's empirical formula is

Answer»

Explanation:

We know that the valency of Oxygen is 2 so the oxidation state is -2 Hence let's take the oxidation state of CHROMIUM to be x so

$x(4.8 \times {10}^{10}) - 2(9.6 \times {10}^{10}) = 0 = >$

$4.8 \times {10}^{10}(x - 4) = 0 = > x = 4$

Hence the oxidation state is 4 so one atom of Chromium is oxidised by two atoms of Oxygen so Empirical formula is CrO2. HOPE it HELPS you.