The no.of moes present rn 50 gr of caco, isa) 2.5moles b)2moles c) 0.5

1.	The no.of moes present rn 50 gr of caco, isa) 2.5moles b)2moles c) 0.5 moles d) 15 miolesThe volume of 0.5 gr of Co, isa) 0.75 lit b) 0.50 lit ) 0.25 lit d) 0.025lit39.40.
Answer» Given mass = 50 g Molecular weight of CaCO3 = 100 g / mol No. of moles (n) = Given mass (m) / Molecular weight (M) n = 50 / 100n = 1 / 2n = 0.5 No. of molecules = n * 6.022 * 10²³= 0.5 * 6.022 * 10²³= 3.011 * 10²³ No. of atoms = 5 * 3.011 * 10²³= 15.055 * 10²³

The no.of moes present rn 50 gr of caco, isa) 2.5moles b)2moles c) 0.5 moles d) 15 miolesThe volume of 0.5 gr of Co, isa) 0.75 lit b) 0.50 lit ) 0.25 lit d) 0.025lit39.40.

Answer»

Given mass = 50 g

Molecular weight of CaCO3 = 100 g / mol

No. of moles (n) = Given mass (m) / Molecular weight (M)

n = 50 / 100n = 1 / 2n = 0.5

No. of molecules = n * 6.022 * 10²³= 0.5 * 6.022 * 10²³= 3.011 * 10²³

No. of atoms = 5 * 3.011 * 10²³= 15.055 * 10²³