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The non - stoichiometric iron oxide has a composition Fe_(0.94) O. Find the ratio of ferrous and ferric ions present in it. |
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Answer» Solution :SAY one hundred ions of each `Fe^(2+) and O^(2-)` present in the stoichiometric `FEO`. Some of `Fe^(2+)`ions (x) are REPLACED by `Fe^(3+)`ions (y). In view of the conservation of ions in an ionic crystal, `x+y=94 ""…(1)` In view of the conservation of positive charge of cations in a crystal, `2x+3y = 200""...(2)` Solving, for .x. and for .y., `y=12 and x=82` The ration of `Fe^(2+) and Fe^(3+)` ions present in `Fe_(0.94) O =82 : 12` `= 41:6` |
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