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The normal density of gold is rho. It.s bulk modulus is K. Find the increase in density of a piece of gold when a pressure Pis applied uniformly from all sides? |
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Answer» <P> Solution :`K=(P)/((dV)/(V)) rArr (dV)/(V)=(P)/(K) and RHO =(M)/(V), rho +Delta rho=(M)/(V-DeltaV) rArr rho=(M)/(V-DeltaV)-(M)/(V)``Delta rho=(M)/(V)[(1)/(1-(DeltaB)/(V))-1] rArr Deltarho=(M)/(V)[(1)/(1-(P)/(K))-1] rArr Delta rho=(M)/(V)[(K)/(K-p)-1] rArr Delta rho =(M)/(V) [(K-K+P)/(K-P)]` `Delta rho=(rho P)/(K-P)` |
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