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The normal to a circle S =0 at P (1,3) is x + 2y -7 and it has another normal at Q(3,5) which is the polar of the pointA(7, -(1)/(2)) with respect to the circle x ^(2) + y ^(2)- 4x + 6y -12 =0. Then the equation of the circle S =0 is |
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Answer» `x ^(2) + y ^(2) -10X -2Y + 6=0` |
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