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The normality of 10% (weight/volume) acetic acid isA. 1 NB. 10 NC. 1.66 ND. 0.83 N |
Answer» Correct Answer - c Normality `= (w)/(E.V) = (10g)/(100 mL)xx(1)/(60)` `= (10g)/((100)/(1000)xx60) = 1.66 N` |
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