1.

The normality of orthophosphoric acid having purity of 70% by weight and specific gravity 1.54 is :

Answer»

11N
22N
33N
44N

SOLUTION :Equivalent weight of orthophosphoric acid`(H_3PO_4)`
`=(3+31+64)/3 = 98/3`
Now 100 G solution contains 70 g `H_3PO_4`
`100/(1000 xx1.54)` litre of solution contains `70/(98//3) g`
equivalent of `H_3PO_4`
Normality of solution
`=((70 xx3)/98)/(1/(10xx1.54))=(70xx3)/98xx10xx1.54 =33N`


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