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The nuclear charge (`Ze`) is non uniformlly distribute with in a nucleus of radius `r`. The charge density `rho(r)` (charge per unit volume) is dependent only on the radial distance r form the centre of the nucleus s shown in figure. The electric field is only along the radial direction. For a=0 the value of d (maximum value of `rho` as shown in the figure) is A. `(3Ze)/(4piR^3)`B. `(3Ze)/(piR^3)`C. `(4Ze)/(3piR^3)`D. `(Ze)/(3piR^3)` |
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Answer» Net charge within `rltR` is constant, hence , electric field is independent of a. `q=int_(0)^(R)(d)/(R)(R-x)4pix^(2)dx=Ze` `d=(3Ze)/(piR^(3))` if within a phere `rho` is constant then `Epropr` |
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