The number density of free electrons in the semiconductor is `10^(18)m – InterviewSolution

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1.	The number density of free electrons in the semiconductor is `10^(18)m^(-3)`. It is doped with a pentavalent impurity atoms of number density `10^(24)m^(-3)`, the number density of free electrons `m^(-3)` increases by a factor ofA. `4//3`B. 6C. `10^(6)`D. `10^(24)`
Answer» Correct Answer - C The number density of free electrons in the doped semiconductor `=10^(18)+10^(24)~~10^(24) m^(-3)`. Increase in number density by a factor `=10^(24)//10^(18)=10^(6)`

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