1.

The number of alpha and beta particles emitted during the transformation of ""_(90)Th^(232) to ""_(82)Pb^(208) are respectively

Answer»

4,2
2,2
8,6
6,4

Solution :`""_(90)Th^(232)to""_(82)Pb^(208)`
Loss in weight=232-208=24.
HENCE number of `alpha`-particles emitted=`(24)/(4)=6`
Therefore,
`""_(90)Th^(232) underset(-6a)to""_(78)X^(208) underset(-4beta)to""_(82)Pb^(208)`
For increasing atomic no. by four units `4beta` particle must be emitted.


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