1.

The number of alpha and beta-particles emitted during the transformation of ._(90)Th^(232) " to " ._(82)Pb^(208) are respectively

Answer»

4, 2
2, 2
8, 6
6, 4

Solution :`._(90)Th^(232) RARR ._(82)Pb^(208) + X ._(2)He^(4) + y ._(-1)BETA^(0)`
Equating mass no.
`232 = 208 + 4x + 0 y or 4x = 24 or x = 6`
Equating atomic no
`90 = 82 + 2x - y or 90 = 82 + 2 xx 6 - y or y = 4`
Hence `6 alpha and 4 beta` particles will be emitted


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