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The number of arrangements of the letters of the word BANANA in which two N’s do not appear adjacently is (A) 80(B) 60(C) 40(D) 100 |
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Answer» (C) 40 Arrange B, A, A, A in \(\frac{4!}{3!}\) ways. These four letters create 5 gaps in which 2 N are to be filled, this can be done in 5C2 ways, we do not permute those 2N as they are identical. ∴ Required number = \(\frac{4!}{3!}\times\,^5C_2=40\) |
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