1.

the number of atoms in 0.1 mole of a triatomic gas is (N_(A)=6.02xx10^(23) mol^(-1))

Answer»

`1.800xx10^(22)`
`6.026xx10^(22)`
`1.806xx10^(23)`
`3.600xx10^(23)`

SOLUTION :No. of ATOMS = No. of MOLECULES `xx` atomicity
`0.1 N_(A)xx3=0.1xx6.02xx10^(23)xx3=1.806xx10^(23)`


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