The number of atoms in 100g of a fcc crystal with density=10gcm^(-3) and cell edge as 200gm, is equal to

The number of atoms in 100g of a fcc crystal with density=10gcm^(-3) a

1.	The number of atoms in 100g of a fcc crystal with density=10gcm^(-3) and cell edge as 200gm, is equal to
Answer» `3xx10^(25)` `5XX10^(24)` `1XX10^(25)` `2xx10^(25)` Solution :(b) We KNOW that, d `(Z.M)/(nxxa^(3))` `N=(4xx100)/(10xx(200xx10^(-10))^(3))` =`5xx10^(24)`