1.

The number of atoms in 2.4 g of body centred cubic crystal with length 200 pm is (density=10 g cm^(-3) ,NA =6xx10^(22) atoms/mol)

Answer»

`6 XX 10^(22)`
`6 xx 10^(20)`
`6 xx 10^(23)`
`6 xx 10^(19)`

Solution :(a): Density, `RHO` = 10 g `cm^(-3)`,
`N_(A) = 6 xx 10^(23)` ATOMS/mol, a= 200 pm, For bcc, Z=2
`rho = (ZxxM)/(a^(3)xxN_(a))`
10 g `cm^(-3) = (2xxM)/((200xx10^(10)cm)^(3)xx(6xx10^(23)mol^(-1)))`
M = 24 g `mol^(-1)`
24 g of element contains = `6xx10^(23)` atoms
`:.` 2.4 g of element contains = `(6xx10^(23))/(24) xx 2.4` atoms
`= 6xx10^(22)` atoms


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