InterviewSolution
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InterviewSolution
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The number of atoms in `4.25 g NH_(3)` is approximately:A. `1.505 xx 10^(23)`B. `6.02 xx 10^(23)`C. `3.01 xx 10^(23)`D. None of these |
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Answer» a) `therefore` 17 g of `NH_(3)` contains = `6.023 xx 10^(23)` molecules of `NH_(3)` `therefore` 4.25 g of `NH_(3)` will contain = `(6.023 xx 10^(23)/(17) xx 425` `=1.505 xx 10^(23)` molecules of `NH_(3)` |
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