The number of atoms in 4.25g of NH_(3) is approximately :

1.	The number of atoms in 4.25g of NH_(3) is approximately :
Answer» `1 XX 10^(23)` `2XX 10^(23)` `4 xx 10^(23)` `6 xx 10^(23)` SOLUTION :4.25 g of `NH_(3)` (= 0.25 mol) 1 mole of `NH_(3)` have atoms `= 4 xx 6.022 xx 10^(23)` 0.25 mole of `NH_(3)` have atoms `= 4 xx 0.25 xx 6.022 xx 10^(23)` `=6.022 xx 10^(23)`.

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